문제 링크: https://www.acmicpc.net/problem/14172
14172번: Moocast
Write a single line of output containing the maximum number of cows a broadcast from a single cow can reach. The originating cow is included in this number.
www.acmicpc.net
DFS
각 cow마다 얼마나 많은 다른 소한테 연결될수 있는지를 구하고, 그 중 최대값을 구하면 됨.
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#include <bits/stdc++.h>
using namespace std;
struct cow {
int x, y, r;
};
int n, check[201];
vector<cow> v;
int dfs(int cur) {
check[cur] = 1;
int ret = 1;
int rr = v[cur].r * v[cur].r;
for(int nxt = 0; nxt < n; nxt++) {
int dd = (v[cur].x-v[nxt].x)*(v[cur].x - v[nxt].x) + (v[cur].y-v[nxt].y)*(v[cur].y-v[nxt].y);
if(!check[nxt] && dd <= rr)
ret += dfs(nxt);
}
return ret;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cin >> n;
for(int i = 0; i < n; i++) {
int x, y, r;
cin >> x >> y >> r;
v.push_back({x, y, r});
}
int ans = 0;
for(int i = 0; i < n; i++) {
memset(check, 0, sizeof(check));
ans = max(ans, dfs(i));
}
cout << ans << '\n';
return 0;
}
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